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1.5x^2+5.5x=0
a = 1.5; b = 5.5; c = 0;
Δ = b2-4ac
Δ = 5.52-4·1.5·0
Δ = 30.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.5)-\sqrt{30.25}}{2*1.5}=\frac{-5.5-\sqrt{30.25}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.5)+\sqrt{30.25}}{2*1.5}=\frac{-5.5+\sqrt{30.25}}{3} $
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