X2=4y2+13

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Solution for X2=4y2+13 equation: 



X2=4X^2+13

We move all terms to the left:

X2-(4X^2+13)=0

We add all the numbers together, and all the variables

X^2-(4X^2+13)=0

We get rid of parentheses

X^2-4X^2-13=0

We add all the numbers together, and all the variables

-3X^2-13=0

a = -3; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·(-3)·(-13)
Δ = -156
Delta is less than zero, so there is no solution for the equation

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