z=(49-51)/30

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Solution for z=(49-51)/30 equation: 



z=(49-51)/30

We move all terms to the left:

z-((49-51)/30)=0

We add all the numbers together, and all the variables

z-((-2)/30)=0

We multiply all the terms by the denominator


z*30)-((-2)=0

Wy multiply elements

30z^2=0

a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{60}=0$

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