2n-3+n=2(n-1)

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Solution for 2n-3+n=2(n-1) equation: 



2n-3+n=2(n-1)

We move all terms to the left:

2n-3+n-(2(n-1))=0

We add all the numbers together, and all the variables

3n-(2(n-1))-3=0



We calculate terms in parentheses: -(2(n-1)), so:

2(n-1)

We multiply parentheses

2n-2

Back to the equation:

-(2n-2)



We get rid of parentheses

3n-2n+2-3=0

We add all the numbers together, and all the variables

n-1=0

We move all terms containing n to the left, all other terms to the right

n=1

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