3(x+3)-8=6(2x-1)

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Solution for 3(x+3)-8=6(2x-1) equation: 



3(x+3)-8=6(2x-1)

We move all terms to the left:

3(x+3)-8-(6(2x-1))=0

We multiply parentheses

3x-(6(2x-1))+9-8=0



We calculate terms in parentheses: -(6(2x-1)), so:

6(2x-1)

We multiply parentheses

12x-6

Back to the equation:

-(12x-6)



We add all the numbers together, and all the variables

3x-(12x-6)+1=0

We get rid of parentheses

3x-12x+6+1=0

We add all the numbers together, and all the variables

-9x+7=0

We move all terms containing x to the left, all other terms to the right

-9x=-7

x=-7/-9

x=7/9

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