2(x+1)=7(x-2)-19

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Solution for 2(x+1)=7(x-2)-19 equation: 



2(x+1)=7(x-2)-19

We move all terms to the left:

2(x+1)-(7(x-2)-19)=0

We multiply parentheses

2x-(7(x-2)-19)+2=0



We calculate terms in parentheses: -(7(x-2)-19), so:

7(x-2)-19

We multiply parentheses

7x-14-19

We add all the numbers together, and all the variables

7x-33

Back to the equation:

-(7x-33)



We get rid of parentheses

2x-7x+33+2=0

We add all the numbers together, and all the variables

-5x+35=0

We move all terms containing x to the left, all other terms to the right

-5x=-35

x=-35/-5

x=+7

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