15y2+26y+8=0

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Solution for 15y2+26y+8=0 equation:



15y^2+26y+8=0
a = 15; b = 26; c = +8;
Δ = b2-4ac
Δ = 262-4·15·8
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*15}=\frac{-40}{30} =-1+1/3 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*15}=\frac{-12}{30} =-2/5 $

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