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2y-5(4y+4)=3-3(5-y)
We move all terms to the left:
2y-5(4y+4)-(3-3(5-y))=0
We add all the numbers together, and all the variables
2y-5(4y+4)-(3-3(-1y+5))=0
We multiply parentheses
2y-20y-(3-3(-1y+5))-20=0
We calculate terms in parentheses: -(3-3(-1y+5)), so:We add all the numbers together, and all the variables
3-3(-1y+5)
determiningTheFunctionDomain -3(-1y+5)+3
We multiply parentheses
3y-15+3
We add all the numbers together, and all the variables
3y-12
Back to the equation:
-(3y-12)
-18y-(3y-12)-20=0
We get rid of parentheses
-18y-3y+12-20=0
We add all the numbers together, and all the variables
-21y-8=0
We move all terms containing y to the left, all other terms to the right
-21y=8
y=8/-21
y=-8/21
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