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3(x+2)-2(x+1)=8+2x
We move all terms to the left:
3(x+2)-2(x+1)-(8+2x)=0
We add all the numbers together, and all the variables
3(x+2)-2(x+1)-(2x+8)=0
We multiply parentheses
3x-2x-(2x+8)+6-2=0
We get rid of parentheses
3x-2x-2x-8+6-2=0
We add all the numbers together, and all the variables
-1x-4=0
We move all terms containing x to the left, all other terms to the right
-x=4
x=4/-1
x=-4
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