n+2n-5=5(n+3)

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Solution for n+2n-5=5(n+3) equation: 



n+2n-5=5(n+3)

We move all terms to the left:

n+2n-5-(5(n+3))=0

We add all the numbers together, and all the variables

3n-(5(n+3))-5=0



We calculate terms in parentheses: -(5(n+3)), so:

5(n+3)

We multiply parentheses

5n+15

Back to the equation:

-(5n+15)



We get rid of parentheses

3n-5n-15-5=0

We add all the numbers together, and all the variables

-2n-20=0

We move all terms containing n to the left, all other terms to the right

-2n=20

n=20/-2

n=-10

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