2(27-)=100-4b+6(3-b)

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Solution for 2(27-)=100-4b+6(3-b) equation: 



2(27-)=100-4b+6(3-b)

We move all terms to the left:

2(27-)-(100-4b+6(3-b))=0

We add all the numbers together, and all the variables

-(100-4b+6(-1b+3))+20=0



We calculate terms in parentheses: -(100-4b+6(-1b+3)), so:

100-4b+6(-1b+3)

determiningTheFunctionDomain
-4b+6(-1b+3)+100

We multiply parentheses

-4b-6b+18+100

We add all the numbers together, and all the variables

-10b+118

Back to the equation:

-(-10b+118)



We get rid of parentheses

10b-118+20=0

We add all the numbers together, and all the variables

10b-98=0

We move all terms containing b to the left, all other terms to the right

10b=98

b=98/10

b=9+4/5

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