(X+11)(x-5)=-64

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Solution for (X+11)(x-5)=-64 equation: 



(X+11)(X-5)=-64

We move all terms to the left:

(X+11)(X-5)-(-64)=0

We add all the numbers together, and all the variables

(X+11)(X-5)+64=0

We multiply parentheses ..

(+X^2-5X+11X-55)+64=0

We get rid of parentheses

X^2-5X+11X-55+64=0

We add all the numbers together, and all the variables

X^2+6X+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{-6}{2}=-3$

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