3(x+1)=-4(2x-3)+14

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Solution for 3(x+1)=-4(2x-3)+14 equation: 



3(x+1)=-4(2x-3)+14

We move all terms to the left:

3(x+1)-(-4(2x-3)+14)=0

We multiply parentheses

3x-(-4(2x-3)+14)+3=0



We calculate terms in parentheses: -(-4(2x-3)+14), so:

-4(2x-3)+14

We multiply parentheses

-8x+12+14

We add all the numbers together, and all the variables

-8x+26

Back to the equation:

-(-8x+26)



We get rid of parentheses

3x+8x-26+3=0

We add all the numbers together, and all the variables

11x-23=0

We move all terms containing x to the left, all other terms to the right

11x=23

x=23/11

x=2+1/11

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