16(2x+5)=22(x+10)

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Solution for 16(2x+5)=22(x+10) equation: 



16(2x+5)=22(x+10)

We move all terms to the left:

16(2x+5)-(22(x+10))=0

We multiply parentheses

32x-(22(x+10))+80=0



We calculate terms in parentheses: -(22(x+10)), so:

22(x+10)

We multiply parentheses

22x+220

Back to the equation:

-(22x+220)



We get rid of parentheses

32x-22x-220+80=0

We add all the numbers together, and all the variables

10x-140=0

We move all terms containing x to the left, all other terms to the right

10x=140

x=140/10

x=14

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