3/2b+b+(2b-90)90(b+45=540

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Solution for 3/2b+b+(2b-90)90(b+45=540 equation: 



3/2b+b+(2b-90)90(b+45=540

We move all terms to the left:

3/2b+b+(2b-90)90(b+45-(540)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We add all the numbers together, and all the variables

b+3/2b+(2b-90)90(b+45-540=0

We multiply all the terms by the denominator


b*2b+((2b-90)90(b+45-540)*2b+3=0

We add all the numbers together, and all the variables

b*2b+((2b-90)90(b-495)*2b+3=0

Wy multiply elements

2b^2+((2b-90)90(b-495)*2b+3=0

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