3x-3(4x+12)=36

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Solution for 3x-3(4x+12)=36 equation: 



3x-3(4x+12)=36

We move all terms to the left:

3x-3(4x+12)-(36)=0

We multiply parentheses

3x-12x-36-36=0

We add all the numbers together, and all the variables

-9x-72=0

We move all terms containing x to the left, all other terms to the right

-9x=72

x=72/-9

x=-8

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