3(v-2)-4=-4(-3v+4)-5v

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Solution for 3(v-2)-4=-4(-3v+4)-5v equation: 



3(v-2)-4=-4(-3v+4)-5v

We move all terms to the left:

3(v-2)-4-(-4(-3v+4)-5v)=0

We multiply parentheses

3v-(-4(-3v+4)-5v)-6-4=0



We calculate terms in parentheses: -(-4(-3v+4)-5v), so:

-4(-3v+4)-5v

We add all the numbers together, and all the variables

-5v-4(-3v+4)

We multiply parentheses

-5v+12v-16

We add all the numbers together, and all the variables

7v-16

Back to the equation:

-(7v-16)



We add all the numbers together, and all the variables

3v-(7v-16)-10=0

We get rid of parentheses

3v-7v+16-10=0

We add all the numbers together, and all the variables

-4v+6=0

We move all terms containing v to the left, all other terms to the right

-4v=-6

v=-6/-4

v=1+1/2

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