-3(u+1)=8u-1+2(2u+2)

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Solution for -3(u+1)=8u-1+2(2u+2) equation: 



-3(u+1)=8u-1+2(2u+2)

We move all terms to the left:

-3(u+1)-(8u-1+2(2u+2))=0

We multiply parentheses

-3u-(8u-1+2(2u+2))-3=0



We calculate terms in parentheses: -(8u-1+2(2u+2)), so:

8u-1+2(2u+2)

determiningTheFunctionDomain
8u+2(2u+2)-1

We multiply parentheses

8u+4u+4-1

We add all the numbers together, and all the variables

12u+3

Back to the equation:

-(12u+3)



We get rid of parentheses

-3u-12u-3-3=0

We add all the numbers together, and all the variables

-15u-6=0

We move all terms containing u to the left, all other terms to the right

-15u=6

u=6/-15

u=-2/5

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