-2(3u-3)+4u=2(4u-4)

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Solution for -2(3u-3)+4u=2(4u-4) equation: 



-2(3u-3)+4u=2(4u-4)

We move all terms to the left:

-2(3u-3)+4u-(2(4u-4))=0

We add all the numbers together, and all the variables

4u-2(3u-3)-(2(4u-4))=0

We multiply parentheses

4u-6u-(2(4u-4))+6=0



We calculate terms in parentheses: -(2(4u-4)), so:

2(4u-4)

We multiply parentheses

8u-8

Back to the equation:

-(8u-8)



We add all the numbers together, and all the variables

-2u-(8u-8)+6=0

We get rid of parentheses

-2u-8u+8+6=0

We add all the numbers together, and all the variables

-10u+14=0

We move all terms containing u to the left, all other terms to the right

-10u=-14

u=-14/-10

u=1+2/5

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