7(x-3)=9(x+2)-5

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Solution for 7(x-3)=9(x+2)-5 equation: 



7(x-3)=9(x+2)-5

We move all terms to the left:

7(x-3)-(9(x+2)-5)=0

We multiply parentheses

7x-(9(x+2)-5)-21=0



We calculate terms in parentheses: -(9(x+2)-5), so:

9(x+2)-5

We multiply parentheses

9x+18-5

We add all the numbers together, and all the variables

9x+13

Back to the equation:

-(9x+13)



We get rid of parentheses

7x-9x-13-21=0

We add all the numbers together, and all the variables

-2x-34=0

We move all terms containing x to the left, all other terms to the right

-2x=34

x=34/-2

x=-17

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