3(v+2)=-3v+48

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Solution for 3(v+2)=-3v+48 equation: 



3(v+2)=-3v+48

We move all terms to the left:

3(v+2)-(-3v+48)=0

We multiply parentheses

3v-(-3v+48)+6=0

We get rid of parentheses

3v+3v-48+6=0

We add all the numbers together, and all the variables

6v-42=0

We move all terms containing v to the left, all other terms to the right

6v=42

v=42/6

v=7

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