3x2-1-x=x(3x+1)+5

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Solution for 3x2-1-x=x(3x+1)+5 equation: 



3x^2-1-x=x(3x+1)+5

We move all terms to the left:

3x^2-1-x-(x(3x+1)+5)=0

We add all the numbers together, and all the variables

3x^2-1x-(x(3x+1)+5)-1=0



We calculate terms in parentheses: -(x(3x+1)+5), so:

x(3x+1)+5

We multiply parentheses

3x^2+x+5

Back to the equation:

-(3x^2+x+5)



We get rid of parentheses

3x^2-3x^2-1x-x-5-1=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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