48=x2+x+(x+8)

Solution for 48=x2+x+(x+8) equation:

48=x2+x+(x+8)

We move all terms to the left:

48-(x2+x+(x+8))=0


We calculate terms in parentheses: -(x2+x+(x+8)), so:

x2+x+(x+8)

We add all the numbers together, and all the variables

x^2+x+(x+8)

We get rid of parentheses

x^2+x+x+8

We add all the numbers together, and all the variables

x^2+2x+8

Back to the equation:

-(x^2+2x+8)


We get rid of parentheses

-x^2-2x-8+48=0

We add all the numbers together, and all the variables

-1x^2-2x+40=0

a = -1; b = -2; c = +40;
Δ = b2-4ac
Δ = -22-4·(-1)·40
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{41}}{2*-1}=\frac{2-2\sqrt{41}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{41}}{2*-1}=\frac{2+2\sqrt{41}}{-2}
$