3(t-6)-4(2t-3)=15-7(3t+4)

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Solution for 3(t-6)-4(2t-3)=15-7(3t+4) equation: 



3(t-6)-4(2t-3)=15-7(3t+4)

We move all terms to the left:

3(t-6)-4(2t-3)-(15-7(3t+4))=0

We multiply parentheses

3t-8t-(15-7(3t+4))-18+12=0



We calculate terms in parentheses: -(15-7(3t+4)), so:

15-7(3t+4)

determiningTheFunctionDomain
-7(3t+4)+15

We multiply parentheses

-21t-28+15

We add all the numbers together, and all the variables

-21t-13

Back to the equation:

-(-21t-13)



We add all the numbers together, and all the variables

-5t-(-21t-13)-6=0

We get rid of parentheses

-5t+21t+13-6=0

We add all the numbers together, and all the variables

16t+7=0

We move all terms containing t to the left, all other terms to the right

16t=-7

t=-7/16

t=-7/16

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