9y-(2y-3)=5(y-2)+2

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Solution for 9y-(2y-3)=5(y-2)+2 equation: 



9y-(2y-3)=5(y-2)+2

We move all terms to the left:

9y-(2y-3)-(5(y-2)+2)=0

We get rid of parentheses

9y-2y-(5(y-2)+2)+3=0



We calculate terms in parentheses: -(5(y-2)+2), so:

5(y-2)+2

We multiply parentheses

5y-10+2

We add all the numbers together, and all the variables

5y-8

Back to the equation:

-(5y-8)



We add all the numbers together, and all the variables

7y-(5y-8)+3=0

We get rid of parentheses

7y-5y+8+3=0

We add all the numbers together, and all the variables

2y+11=0

We move all terms containing y to the left, all other terms to the right

2y=-11

y=-11/2

y=-5+1/2

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