3(t-2)-2(3t-2)=2-6(5t+1)

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Solution for 3(t-2)-2(3t-2)=2-6(5t+1) equation: 



3(t-2)-2(3t-2)=2-6(5t+1)

We move all terms to the left:

3(t-2)-2(3t-2)-(2-6(5t+1))=0

We multiply parentheses

3t-6t-(2-6(5t+1))-6+4=0



We calculate terms in parentheses: -(2-6(5t+1)), so:

2-6(5t+1)

determiningTheFunctionDomain
-6(5t+1)+2

We multiply parentheses

-30t-6+2

We add all the numbers together, and all the variables

-30t-4

Back to the equation:

-(-30t-4)



We add all the numbers together, and all the variables

-3t-(-30t-4)-2=0

We get rid of parentheses

-3t+30t+4-2=0

We add all the numbers together, and all the variables

27t+2=0

We move all terms containing t to the left, all other terms to the right

27t=-2

t=-2/27

t=-2/27

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