-22+3h=4-2(h-1)-2h

Solution for -22+3h=4-2(h-1)-2h equation:

-22+3h=4-2(h-1)-2h

We move all terms to the left:

-22+3h-(4-2(h-1)-2h)=0


We calculate terms in parentheses: -(4-2(h-1)-2h), so:

4-2(h-1)-2h

determiningTheFunctionDomain
-2(h-1)-2h+4

We add all the numbers together, and all the variables

-2h-2(h-1)+4

We multiply parentheses

-2h-2h+2+4

We add all the numbers together, and all the variables

-4h+6

Back to the equation:

-(-4h+6)


We get rid of parentheses

3h+4h-6-22=0

We add all the numbers together, and all the variables

7h-28=0

We move all terms containing h to the left, all other terms to the right

7h=28

h=28/7

h=4