3(p+4)-12=2(p+9)

Solution for 3(p+4)-12=2(p+9) equation:

3(p+4)-12=2(p+9)

We move all terms to the left:

3(p+4)-12-(2(p+9))=0

We multiply parentheses

3p-(2(p+9))+12-12=0


We calculate terms in parentheses: -(2(p+9)), so:

2(p+9)

We multiply parentheses

2p+18

Back to the equation:

-(2p+18)


We add all the numbers together, and all the variables

3p-(2p+18)=0

We get rid of parentheses

3p-2p-18=0

We add all the numbers together, and all the variables

p-18=0

We move all terms containing p to the left, all other terms to the right

p=18