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-3=1/5(10s-5)
We move all terms to the left:
-3-(1/5(10s-5))=0
Domain of the equation: 5(10s-5))!=0We multiply all the terms by the denominator
s∈R
-(1-3*5(10s-5))=0
We calculate terms in parentheses: -(1-3*5(10s-5)), so:We add all the numbers together, and all the variables
1-3*5(10s-5)
determiningTheFunctionDomain -3*5(10s-5)+1
Wy multiply elements
-15s(1+1
Back to the equation:
-(-15s(1+1)
-(-15s2=0
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