-5(2-y)+6=5-3(4+y)

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Solution for -5(2-y)+6=5-3(4+y) equation: 



-5(2-y)+6=5-3(4+y)

We move all terms to the left:

-5(2-y)+6-(5-3(4+y))=0

We add all the numbers together, and all the variables

-5(-1y+2)-(5-3(y+4))+6=0

We multiply parentheses

5y-(5-3(y+4))-10+6=0



We calculate terms in parentheses: -(5-3(y+4)), so:

5-3(y+4)

determiningTheFunctionDomain
-3(y+4)+5

We multiply parentheses

-3y-12+5

We add all the numbers together, and all the variables

-3y-7

Back to the equation:

-(-3y-7)



We add all the numbers together, and all the variables

5y-(-3y-7)-4=0

We get rid of parentheses

5y+3y+7-4=0

We add all the numbers together, and all the variables

8y+3=0

We move all terms containing y to the left, all other terms to the right

8y=-3

y=-3/8

y=-3/8

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