4+2(5-y)=-8+2(y+3)

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Solution for 4+2(5-y)=-8+2(y+3) equation: 



4+2(5-y)=-8+2(y+3)

We move all terms to the left:

4+2(5-y)-(-8+2(y+3))=0

We add all the numbers together, and all the variables

2(-1y+5)-(-8+2(y+3))+4=0

We multiply parentheses

-2y-(-8+2(y+3))+10+4=0



We calculate terms in parentheses: -(-8+2(y+3)), so:

-8+2(y+3)

determiningTheFunctionDomain
2(y+3)-8

We multiply parentheses

2y+6-8

We add all the numbers together, and all the variables

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

-2y-(2y-2)+14=0

We get rid of parentheses

-2y-2y+2+14=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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