3(n-4)=5(n+4)-2

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Solution for 3(n-4)=5(n+4)-2 equation: 



3(n-4)=5(n+4)-2

We move all terms to the left:

3(n-4)-(5(n+4)-2)=0

We multiply parentheses

3n-(5(n+4)-2)-12=0



We calculate terms in parentheses: -(5(n+4)-2), so:

5(n+4)-2

We multiply parentheses

5n+20-2

We add all the numbers together, and all the variables

5n+18

Back to the equation:

-(5n+18)



We get rid of parentheses

3n-5n-18-12=0

We add all the numbers together, and all the variables

-2n-30=0

We move all terms containing n to the left, all other terms to the right

-2n=30

n=30/-2

n=-15

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