3(n-1)=2(n+4)

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Solution for 3(n-1)=2(n+4) equation: 



3(n-1)=2(n+4)

We move all terms to the left:

3(n-1)-(2(n+4))=0

We multiply parentheses

3n-(2(n+4))-3=0



We calculate terms in parentheses: -(2(n+4)), so:

2(n+4)

We multiply parentheses

2n+8

Back to the equation:

-(2n+8)



We get rid of parentheses

3n-2n-8-3=0

We add all the numbers together, and all the variables

n-11=0

We move all terms containing n to the left, all other terms to the right

n=11

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