-(x-9)+4(-2x+1)-7(3x-5)=-4(8x-12)+3

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Solution for -(x-9)+4(-2x+1)-7(3x-5)=-4(8x-12)+3 equation: 



-(x-9)+4(-2x+1)-7(3x-5)=-4(8x-12)+3

We move all terms to the left:

-(x-9)+4(-2x+1)-7(3x-5)-(-4(8x-12)+3)=0

We multiply parentheses

-(x-9)-8x-21x-(-4(8x-12)+3)+4+35=0

We get rid of parentheses

-x-8x-21x-(-4(8x-12)+3)+9+4+35=0



We calculate terms in parentheses: -(-4(8x-12)+3), so:

-4(8x-12)+3

We multiply parentheses

-32x+48+3

We add all the numbers together, and all the variables

-32x+51

Back to the equation:

-(-32x+51)



We add all the numbers together, and all the variables

-30x-(-32x+51)+48=0

We get rid of parentheses

-30x+32x-51+48=0

We add all the numbers together, and all the variables

2x-3=0

We move all terms containing x to the left, all other terms to the right

2x=3

x=3/2

x=1+1/2

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