8(t+2)-4(t-4=6(t-7)+8

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Solution for 8(t+2)-4(t-4=6(t-7)+8 equation: 



8(t+2)-4(t-4=6(t-7)+8

We move all terms to the left:

8(t+2)-4(t-4-(6(t-7)+8)=0

We multiply parentheses

8t-4(t-4-(6(t-7)+8)+16=0

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