-2(x+3)=3(x-2)

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Solution for -2(x+3)=3(x-2) equation: 



-2(x+3)=3(x-2)

We move all terms to the left:

-2(x+3)-(3(x-2))=0

We multiply parentheses

-2x-(3(x-2))-6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-2x-3x+6-6=0

We add all the numbers together, and all the variables

-5x=0

x=0/-5

x=0

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