3(m+3)-5=2(m+2)

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Solution for 3(m+3)-5=2(m+2) equation: 



3(m+3)-5=2(m+2)

We move all terms to the left:

3(m+3)-5-(2(m+2))=0

We multiply parentheses

3m-(2(m+2))+9-5=0



We calculate terms in parentheses: -(2(m+2)), so:

2(m+2)

We multiply parentheses

2m+4

Back to the equation:

-(2m+4)



We add all the numbers together, and all the variables

3m-(2m+4)+4=0

We get rid of parentheses

3m-2m-4+4=0

We add all the numbers together, and all the variables

m=0

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