3(k-4)=6(k+2)

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Solution for 3(k-4)=6(k+2) equation: 



3(k-4)=6(k+2)

We move all terms to the left:

3(k-4)-(6(k+2))=0

We multiply parentheses

3k-(6(k+2))-12=0



We calculate terms in parentheses: -(6(k+2)), so:

6(k+2)

We multiply parentheses

6k+12

Back to the equation:

-(6k+12)



We get rid of parentheses

3k-6k-12-12=0

We add all the numbers together, and all the variables

-3k-24=0

We move all terms containing k to the left, all other terms to the right

-3k=24

k=24/-3

k=-8

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