2/3b=6-5/6b

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Solution for 2/3b=6-5/6b equation:



2/3b=6-5/6b
We move all terms to the left:
2/3b-(6-5/6b)=0
Domain of the equation: 3b!=0
b!=0/3
b!=0
b∈R
Domain of the equation: 6b)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
2/3b-(-5/6b+6)=0
We get rid of parentheses
2/3b+5/6b-6=0
We calculate fractions
12b/18b^2+15b/18b^2-6=0
We multiply all the terms by the denominator
12b+15b-6*18b^2=0
We add all the numbers together, and all the variables
27b-6*18b^2=0
Wy multiply elements
-108b^2+27b=0
a = -108; b = 27; c = 0;
Δ = b2-4ac
Δ = 272-4·(-108)·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-27}{2*-108}=\frac{-54}{-216} =1/4 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+27}{2*-108}=\frac{0}{-216} =0 $

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