3(9-a)=(2a+3)+16a

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Solution for 3(9-a)=(2a+3)+16a equation: 



3(9-a)=(2a+3)+16a

We move all terms to the left:

3(9-a)-((2a+3)+16a)=0

We add all the numbers together, and all the variables

3(-1a+9)-((2a+3)+16a)=0

We multiply parentheses

-3a-((2a+3)+16a)+27=0



We calculate terms in parentheses: -((2a+3)+16a), so:

(2a+3)+16a

We add all the numbers together, and all the variables

16a+(2a+3)

We get rid of parentheses

16a+2a+3

We add all the numbers together, and all the variables

18a+3

Back to the equation:

-(18a+3)



We get rid of parentheses

-3a-18a-3+27=0

We add all the numbers together, and all the variables

-21a+24=0

We move all terms containing a to the left, all other terms to the right

-21a=-24

a=-24/-21

a=1+1/7

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