2(y+2)+y=19-(2+3y)

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Solution for 2(y+2)+y=19-(2+3y) equation: 



2(y+2)+y=19-(2+3y)

We move all terms to the left:

2(y+2)+y-(19-(2+3y))=0

We add all the numbers together, and all the variables

2(y+2)+y-(19-(3y+2))=0

We add all the numbers together, and all the variables

y+2(y+2)-(19-(3y+2))=0

We multiply parentheses

y+2y-(19-(3y+2))+4=0



We calculate terms in parentheses: -(19-(3y+2)), so:

19-(3y+2)

determiningTheFunctionDomain
-(3y+2)+19

We get rid of parentheses

-3y-2+19

We add all the numbers together, and all the variables

-3y+17

Back to the equation:

-(-3y+17)



We add all the numbers together, and all the variables

3y-(-3y+17)+4=0

We get rid of parentheses

3y+3y-17+4=0

We add all the numbers together, and all the variables

6y-13=0

We move all terms containing y to the left, all other terms to the right

6y=13

y=13/6

y=2+1/6

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