2(y+2)+y=19(2+3y)

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Solution for 2(y+2)+y=19(2+3y) equation: 



2(y+2)+y=19(2+3y)

We move all terms to the left:

2(y+2)+y-(19(2+3y))=0

We add all the numbers together, and all the variables

2(y+2)+y-(19(3y+2))=0

We add all the numbers together, and all the variables

y+2(y+2)-(19(3y+2))=0

We multiply parentheses

y+2y-(19(3y+2))+4=0



We calculate terms in parentheses: -(19(3y+2)), so:

19(3y+2)

We multiply parentheses

57y+38

Back to the equation:

-(57y+38)



We add all the numbers together, and all the variables

3y-(57y+38)+4=0

We get rid of parentheses

3y-57y-38+4=0

We add all the numbers together, and all the variables

-54y-34=0

We move all terms containing y to the left, all other terms to the right

-54y=34

y=34/-54

y=-17/27

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