2s+4=s(-4-2s)

Solution for 2s+4=s(-4-2s) equation:

2s+4=s(-4-2s)

We move all terms to the left:

2s+4-(s(-4-2s))=0

We add all the numbers together, and all the variables

2s-(s(-2s-4))+4=0


We calculate terms in parentheses: -(s(-2s-4)), so:

s(-2s-4)

We multiply parentheses

-2s^2-4s

Back to the equation:

-(-2s^2-4s)


We get rid of parentheses

2s^2+4s+2s+4=0

We add all the numbers together, and all the variables

2s^2+6s+4=0

a = 2; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·2·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2}{2*2}=\frac{-8}{4}
=-2
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2}{2*2}=\frac{-4}{4}
=-1
$