3(5c-4)-2=4(3c+7)

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Solution for 3(5c-4)-2=4(3c+7) equation: 



3(5c-4)-2=4(3c+7)

We move all terms to the left:

3(5c-4)-2-(4(3c+7))=0

We multiply parentheses

15c-(4(3c+7))-12-2=0



We calculate terms in parentheses: -(4(3c+7)), so:

4(3c+7)

We multiply parentheses

12c+28

Back to the equation:

-(12c+28)



We add all the numbers together, and all the variables

15c-(12c+28)-14=0

We get rid of parentheses

15c-12c-28-14=0

We add all the numbers together, and all the variables

3c-42=0

We move all terms containing c to the left, all other terms to the right

3c=42

c=42/3

c=14

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