(N+1)(n)/(n-1)=132

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Solution for (N+1)(n)/(n-1)=132 equation: 



(+1)(N)/(N-1)=132

We move all terms to the left:

(+1)(N)/(N-1)-(132)=0



Domain of the equation: (N-1)!=0

We move all terms containing N to the left, all other terms to the right

N!=1

N∈R



We add all the numbers together, and all the variables

1N/(N-1)-132=0

We multiply all the terms by the denominator


1N-132*(N-1)=0

We add all the numbers together, and all the variables

N-132*(N-1)=0

We multiply parentheses

N-132N+132=0

We add all the numbers together, and all the variables

-131N+132=0

We move all terms containing N to the left, all other terms to the right

-131N=-132

N=-132/-131

N=1+1/131

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