6x-4=3(2-x)+2(x-1)

Solution for 6x-4=3(2-x)+2(x-1) equation:

6x-4=3(2-x)+2(x-1)

We move all terms to the left:

6x-4-(3(2-x)+2(x-1))=0

We add all the numbers together, and all the variables

6x-(3(-1x+2)+2(x-1))-4=0


We calculate terms in parentheses: -(3(-1x+2)+2(x-1)), so:

3(-1x+2)+2(x-1)

We multiply parentheses

-3x+2x+6-2

We add all the numbers together, and all the variables

-1x+4

Back to the equation:

-(-1x+4)


We get rid of parentheses

6x+1x-4-4=0

We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7