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10a=3(3a-4)+15
We move all terms to the left:
10a-(3(3a-4)+15)=0
We calculate terms in parentheses: -(3(3a-4)+15), so:We get rid of parentheses
3(3a-4)+15
We multiply parentheses
9a-12+15
We add all the numbers together, and all the variables
9a+3
Back to the equation:
-(9a+3)
10a-9a-3=0
We add all the numbers together, and all the variables
a-3=0
We move all terms containing a to the left, all other terms to the right
a=3
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