3(4b-2)=6(1-2b)

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Solution for 3(4b-2)=6(1-2b) equation: 



3(4b-2)=6(1-2b)

We move all terms to the left:

3(4b-2)-(6(1-2b))=0

We add all the numbers together, and all the variables

3(4b-2)-(6(-2b+1))=0

We multiply parentheses

12b-(6(-2b+1))-6=0



We calculate terms in parentheses: -(6(-2b+1)), so:

6(-2b+1)

We multiply parentheses

-12b+6

Back to the equation:

-(-12b+6)



We get rid of parentheses

12b+12b-6-6=0

We add all the numbers together, and all the variables

24b-12=0

We move all terms containing b to the left, all other terms to the right

24b=12

b=12/24

b=1/2

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