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3(3x-1)+3(3x-3)=5(2x+2)
We move all terms to the left:
3(3x-1)+3(3x-3)-(5(2x+2))=0
We multiply parentheses
9x+9x-(5(2x+2))-3-9=0
We calculate terms in parentheses: -(5(2x+2)), so:We add all the numbers together, and all the variables
5(2x+2)
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
18x-(10x+10)-12=0
We get rid of parentheses
18x-10x-10-12=0
We add all the numbers together, and all the variables
8x-22=0
We move all terms containing x to the left, all other terms to the right
8x=22
x=22/8
x=2+3/4
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