3c+3(6-2c)=27

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Solution for 3c+3(6-2c)=27 equation: 



3c+3(6-2c)=27

We move all terms to the left:

3c+3(6-2c)-(27)=0

We add all the numbers together, and all the variables

3c+3(-2c+6)-27=0

We multiply parentheses

3c-6c+18-27=0

We add all the numbers together, and all the variables

-3c-9=0

We move all terms containing c to the left, all other terms to the right

-3c=9

c=9/-3

c=-3

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